$\lim _{n \rightarrow \infty} \sum_{k=1}^n \frac{k}{n^2+k^2} = $

  • A
    $\frac{1}{2} \log 2$
  • B
    $2 \log 2$
  • C
    $\frac{1}{3} \log 2$
  • D
    $3 \log 2$

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Similar Questions

$\lim _{n \rightarrow \infty} \left( \frac{1}{\sqrt{4n^2-1}} + \frac{1}{\sqrt{4n^2-4}} + \dots + \frac{1}{\sqrt{4n^2-n^2}} \right)$ का मान है

मान लीजिए $\lim _{n \rightarrow \infty} \sum_{r=1}^{n} \left( \frac{n}{\sqrt{n^4+r^4}} - \frac{2 n r^2}{(n^2+r^2) \sqrt{n^4+r^4}} \right) = \frac{\pi}{k}.$ प्रतिलोम त्रिकोणमितीय फलनों के मुख्य मानों का उपयोग करते हुए,$k^2$ का मान ज्ञात कीजिए:

$\lim _{n \rightarrow \infty}\left\{\frac{1}{n+m}+\frac{1}{n+2 m}+\frac{1}{n+3 m}+\ldots+\frac{1}{n+n m}\right\}=$

यदि $f: R \rightarrow R$ को $f(x)=x+1$ द्वारा परिभाषित किया गया है,तो $\lim _{n \rightarrow \infty} \frac{1}{n}\left[f(0)+f\left(\frac{5}{n}\right)+f\left(\frac{10}{n}\right)+\ldots+f\left(\frac{5(n-1)}{n}\right)\right]$ का मान ज्ञात कीजिए।

$\lim _{n \rightarrow \infty} \frac{(2n(2n-1) \dots (n+1))^{1/n}}{n} = $

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