(B) We know the identity $\sin^{-1}(\theta) + \cos^{-1}(\theta) = \frac{\pi}{2}$ for $\theta \in [-1, 1]$.In the given expression,let $\theta = \sqrt{

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(B) We know the identity $\sin^{-1}(\theta) + \cos^{-1}(\theta) = \frac{\pi}{2}$ for $\theta \in [-1, 1]$.In the given expression,let $\theta = \sqrt{1-x}$.For the expression to be defined,we must have $0 \le 1-x \le 1$,which implies $0 \le x \le 1$.Thus,$\cos^{-1}\sqrt{1-x} + \sin^{-1}\sqrt{1-x} = \frac{\pi}{2}$.