sin (2{sin ^{ - 1}}0.8) = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $	heta = \sin^{-1}(0.8)$. Then $\sin 	heta = 0.8 = \frac{4}{5}$.We need to find $\sin(2	heta)$.Using the identity $\sin(2	heta) = 2 \sin \

Vedclass · Accepted Answer

$0.96$

Vedclass · Answer

(A) Let $	heta = \sin^{-1}(0.8)$. Then $\sin 	heta = 0.8 = \frac{4}{5}$.We need to find $\sin(2	heta)$.Using the identity $\sin(2	heta) = 2 \sin 	heta \cos 	heta$.Since $\sin 	heta = \frac{4}{5}$,we have $\cos 	heta = \sqrt{1 - \sin^2 	heta} = \sqrt{1 - (\frac{4}{5})^2} = \sqrt{1 - \frac{16}{25}} = \sqrt{\frac{9}{25}} = \frac{3}{5}$.Therefore,$\sin(2	heta) = 2 	imes \frac{4}{5} 	imes \frac{3}{5} = \frac{24}{25} = 0.96$.

$\sin (2{\sin ^{ - 1}}0.8) = $

Similar Questions

Consider a function $f: [-1, 1] \to R$ where $f(x) = \alpha_1 \sin^{-1} x + \alpha_3 (\sin^{-1} x)^3 + \dots + \alpha_{2n+1} (\sin^{-1} x)^{2n+1} - \cot^{-1} x$,where $\alpha_i$ are positive constants and $n \in N < 100$. Then $f(x)$ is:

Find the value of $\sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)$

$\sin^{-1} (\sin \frac{3\pi}{5}) = \dots \dots \dots$

The value of $\sin \left(2 \sin ^{-1} 0.8\right)$ is equal to

$\tan \left[ \sec^{-1} \sqrt{1 + x^2} \right] = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module