A rifle of 20 ,kg mass can fire 4 bullets per | vedclass

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(D) The force exerted by the bullets on the rifle is equal to the rate of change of momentum of the bullets.Given:Mass of rifle $M = 20 \,kg$Number of

Vedclass · Accepted Answer

$56$

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(D) The force exerted by the bullets on the rifle is equal to the rate of change of momentum of the bullets.Given:Mass of rifle $M = 20 \,kg$Number of bullets per second $n = 4$Mass of each bullet $m = 35 	imes 10^{-3} \,kg$Velocity of each bullet $v = 400 \,ms^{-1}$The force $F$ required to keep the rifle stationary is equal to the recoil force exerted by the bullets.The recoil force is given by the rate of change of momentum of the bullets:$F = n 	imes (m 	imes v)$$F = 4 	imes (35 	imes 10^{-3} \,kg) 	imes (400 \,ms^{-1})$$F = 4 	imes 35 	imes 0.4$$F = 140 	imes 0.4 = 56 \,N$To prevent the rifle from moving backwards,an external force of $56 \,N$ must be applied in the direction of the bullet's motion.

$A$ rifle of $20 \,kg$ mass can fire $4$ bullets per second. The mass of each bullet is $35 \times 10^{-3} \,kg$ and its final velocity is $400 \,ms^{-1}$. What force must be applied on the rifle so that it does not move backwards while firing the bullets (in $\,N$)?

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