The polarising angle of a transparent medium is $\theta$. Let the speed of light in the medium be $v$. Then the relation between $\theta$ and $v$ is [where $c$ is the velocity of light in air].

  • A
    $\theta=\sin ^{-1}\left(\frac{v}{c}\right)$
  • B
    $\theta=\tan ^{-1}\left(\frac{v}{c}\right)$
  • C
    $\theta=\cot ^{-1}\left(\frac{v}{c}\right)$
  • D
    $\theta=\cos ^{-1}\left(\frac{v}{c}\right)$

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