The refractive index of a medium is equal to the tangent of the polarizing angle. This is known as:

The angle of polarisation for a medium is $60^o$. What will be the critical angle for this medium?

$A$ ray of light is incident at a polarising angle such that its deviation is $24^{\circ}$. Then the angle of incidence is: (in $^{\circ}$)

At what angle should an unpolarised beam be incident on a crystal of $\mu = \sqrt{3}$,so that the reflected beam is polarised (in $^{\circ}$)?

An unpolarized light beam travelling in air is incident on a medium of refractive index $1.73$ at Brewster's angle. Then

$A$ ray of light is incident at the polarising angle $\theta$ on an air-glass interface. If $\lambda_{a}$ and $\lambda_{g}$ are the wavelengths of light in air and glass respectively,then: