A parallel beam of light of wavelength 6000 t | vedclass

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(A) For a single slit diffraction, the condition for the $n^{th}$ minima is given by $a \sin 	heta = n \lambda$, where $a$ is the slit width, $\lambd

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$2 	imes 10^{-3} 	ext{ rad}$

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(A) For a single slit diffraction, the condition for the $n^{th}$ minima is given by $a \sin 	heta = n \lambda$, where $a$ is the slit width, $\lambda$ is the wavelength, and $	heta$ is the angular position.Given: $\lambda = 6000 	ext{ Å} = 6000 	imes 10^{-10} 	ext{ m} = 6 	imes 10^{-7} 	ext{ m}$ and $a = 0.3 	ext{ mm} = 0.3 	imes 10^{-3} 	ext{ m} = 3 	imes 10^{-4} 	ext{ m}$.For the first minima, $n = 1$.Substituting the values: $3 	imes 10^{-4} \sin 	heta = 1 	imes 6 	imes 10^{-7}$.$\sin 	heta = \frac{6 	imes 10^{-7}}{3 	imes 10^{-4}} = 2 	imes 10^{-3}$.Since $	heta$ is very small, $\sin 	heta \approx 	heta$.Therefore, $	heta = 2 	imes 10^{-3} 	ext{ rad}$.

$A$ parallel beam of light of wavelength $6000 \text{ Å}$ is diffracted by a single slit of width $0.3 \text{ mm}$. The angular position of the first minima of the diffracted light is

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