A neutron,a proton,an electron,and an alpha-p | vedclass

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(D) The radius of the circular path of a charged particle moving in a uniform magnetic field is given by $r = \frac{mv}{qB}$.Since the particles enter

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$D$

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(D) The radius of the circular path of a charged particle moving in a uniform magnetic field is given by $r = \frac{mv}{qB}$.Since the particles enter with the same velocity $v$ in the same magnetic field $B$,the radius $r$ is directly proportional to the mass-to-charge ratio,i.e.,$r \propto \frac{m}{q}$.$1$. $A$ neutron is neutral $(q=0)$,so it experiences no magnetic force and follows a straight path,which is track $C$.$2$. The electron is negatively charged,while the proton and $\alpha$-particle are positively charged. According to Fleming's Left-Hand Rule,the electron will deflect in the opposite direction to the positively charged particles.$3$. Among the charged particles,the electron has the smallest mass-to-charge ratio $(m/q)$. Therefore,it will have the smallest radius of curvature.$4$. Since the electron is negatively charged and has the smallest radius,it follows track $D$.

$A$ neutron,a proton,an electron,and an $\alpha$-particle enter a region of uniform magnetic field with the same velocities. The magnetic field is perpendicular and directed into the plane of the paper. The tracks of the particles are labeled in the figure. Which track does the electron follow?

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