(A) We need to evaluate the definite integral $I = \int_{0}^{\pi} \sin x \, dx$. The antiderivative of $\sin x$ is $-\cos x$. Applying the Fundamental

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(A) We need to evaluate the definite integral $I = \int_{0}^{\pi} \sin x \, dx$. The antiderivative of $\sin x$ is $-\cos x$. Applying the Fundamental Theorem of Calculus: $I = [-\cos x]_{0}^{\pi}$ $I = -(\cos \pi - \cos 0)$ $I = -(-1 - 1)$ $I = -(-2)$ $I = 2$ Therefore,the correct option is $A$.