sin left(cos ^{-1}left(-frac{1}{7}right)+sin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We know the identity $\sin^{-1}(x) + \cos^{-1}(x) = \frac{\pi}{2}$ for $x \in [-1, 1]$.Here,let $x = -\frac{1}{7}$.Since $-\frac{1}{7} \in [-1, 1]

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) We know the identity $\sin^{-1}(x) + \cos^{-1}(x) = \frac{\pi}{2}$ for $x \in [-1, 1]$.Here,let $x = -\frac{1}{7}$.Since $-\frac{1}{7} \in [-1, 1]$,we can apply the identity.Therefore,$\cos^{-1}\left(-\frac{1}{7}\right) + \sin^{-1}\left(-\frac{1}{7}\right) = \frac{\pi}{2}$.Substituting this into the original expression,we get $\sin\left(\frac{\pi}{2}\right)$.Since $\sin\left(\frac{\pi}{2}\right) = 1$,the final answer is $1$.

$\sin \left(\cos ^{-1}\left(-\frac{1}{7}\right)+\sin ^{-1}\left(-\frac{1}{7}\right)\right) = $ . . . . . . .

Similar Questions

The value of $\cot \left(\sum_{n=1}^{23} \cot ^{-1}\left(1+\sum_{k=1}^n 2 k\right)\right)$ is

$\cos ^{-1}\left(\frac{-1}{2}\right)-2 \sin ^{-1}\left(\frac{1}{2}\right)+3 \cos ^{-1}\left(\frac{-1}{\sqrt{2}}\right)-4 \tan ^{-1}(-1)$ equals

$\frac{d}{dx} \left[ \tan^{-1} \left( \frac{a - x}{1 + ax} \right) \right] = $

The value of the expression $ \tan \left(\frac{1}{2} \cos ^{-1} \frac{2}{\sqrt{5}}\right) $ is

If $\sin^{-1} x + \sin^{-1} y + \sin^{-1} z = \frac{\pi}{2}$,then the value of $x^2 + y^2 + z^2 + 2xyz$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module