(B) The fringe width $\beta$ in a medium of refractive index $\mu$ is given by $\beta = \frac{\lambda_w D}{d}$.Here, the wavelength in water is $\lamb

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(B) The fringe width $\beta$ in a medium of refractive index $\mu$ is given by $\beta = \frac{\lambda_w D}{d}$.Here, the wavelength in water is $\lambda_w = \frac{\lambda_{air}}{\mu} = \frac{6300 \times 10^{-10} \,m}{1.33}$.Given: $D = 1.33 \,m$, $d = 1 \,mm = 10^{-3} \,m$, and $\mu = 1.33$.Substituting these values into the formula:$\beta = \frac{(6300 \times 10^{-10} / 1.33) \times 1.33}{10^{-3}} \,m$.$\beta = \frac{6300 \times 10^{-10}}{10^{-3}} \,m$.$\beta = 6300 \times 10^{-7} \,m = 6.3 \times 10^{-4} \,m$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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$A$ double slit experiment is immersed in water of refractive index $1.33$. The slit separation is $1 \,mm$, and the distance between the slit and the screen is $1.33 \,m$. The slits are illuminated by light of wavelength $6300 \,Å$. The fringe width is:

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A
$6.9 \times 10^{-4} \,m$
B
$6.3 \times 10^{-4} \,m$
C
$5.8 \times 10^{-4} \,m$
D
$8.6 \times 10^{-4} \,m$

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Wave Optics

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Young's Double Slit Experiment (YDSE)

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In $YDSE$,the $Y$-coordinates of the central maxima and the $10^{th}$ maxima are $2 \, cm$ and $5 \, cm$ respectively. When the $YDSE$ apparatus is immersed in a liquid of refractive index $1.5$,what will be the corresponding $Y$-coordinates?

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In a Young's double-slit experiment,light of wavelength $5890 \ \mathring A$ is used,and the angular fringe width on the screen is $0.20^\circ$. If the entire apparatus is immersed in water,find the new angular fringe width. (Refractive index of water $\mu = 4/3$) (in $^\circ$)

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In $YDSE$,how many maxima can be obtained on the screen if the wavelength of light used is $200 \, nm$ and $d = 700 \, nm$?

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In a Young's double-slit experiment, interference fringes are obtained on a screen at a distance of $1 \, m$ using light of wavelength $6000 \, \mathring{A}$. The distance between the slits is $1 \, mm$. The fringe width is:

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In a Young's double-slit experiment,two slits are separated by a distance of $3 \, mm$ and are illuminated by light of wavelength $480 \, nm$. The screen is at a distance of $2 \, m$ from the plane of the slits. Find the separation between the $8^{th}$ bright fringe and the $3^{rd}$ dark fringe with respect to the central fringe.

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$A$ double slit experiment is immersed in water of refractive index $1.33$. The slit separation is $1 \,mm$, and the distance between the slit and the screen is $1.33 \,m$. The slits are illuminated by light of wavelength $6300 \,Å$. The fringe width is:

Similar Questions

In $YDSE$,the $Y$-coordinates of the central maxima and the $10^{th}$ maxima are $2 \, cm$ and $5 \, cm$ respectively. When the $YDSE$ apparatus is immersed in a liquid of refractive index $1.5$,what will be the corresponding $Y$-coordinates?

In a Young's double-slit experiment,light of wavelength $5890 \ \mathring A$ is used,and the angular fringe width on the screen is $0.20^\circ$. If the entire apparatus is immersed in water,find the new angular fringe width. (Refractive index of water $\mu = 4/3$) (in $^\circ$)

In $YDSE$,how many maxima can be obtained on the screen if the wavelength of light used is $200 \, nm$ and $d = 700 \, nm$?

In a Young's double-slit experiment, interference fringes are obtained on a screen at a distance of $1 \, m$ using light of wavelength $6000 \, \mathring{A}$. The distance between the slits is $1 \, mm$. The fringe width is:

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