In a Young's double-slit experiment, interference fringes are obtained on a screen at a distance of $1 \, m$ using light of wavelength $6000 \, \mathring{A}$. The distance between the slits is $1 \, mm$. The fringe width is:
- A$3 \times 10^{-4} \, m$
- B$6 \times 10^{-4} \, m$
- C$3 \times 10^{-3} \, m$
- D$6 \times 10^{-3} \, m$
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