A student scores the following marks in five | vedclass

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(B) Let the sixth test score be $x$. Given the mean of six tests is $48$,we have: $\frac{54+45+41+43+57+x}{6} = 48$ $240 + x = 288$ $x = 48$. The mark

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$\frac{10}{\sqrt{3}}$

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(B) Let the sixth test score be $x$. Given the mean of six tests is $48$,we have: $\frac{54+45+41+43+57+x}{6} = 48$ $240 + x = 288$ $x = 48$. The marks are $54, 45, 41, 43, 57, 48$. The mean $\bar{x} = 48$. The standard deviation $\sigma = \sqrt{\frac{1}{n} \sum (x_i - \bar{x})^2}$. $\sigma = \sqrt{\frac{(54-48)^2 + (45-48)^2 + (41-48)^2 + (43-48)^2 + (57-48)^2 + (48-48)^2}{6}}$ $\sigma = \sqrt{\frac{6^2 + (-3)^2 + (-7)^2 + (-5)^2 + 9^2 + 0^2}{6}}$ $\sigma = \sqrt{\frac{36 + 9 + 49 + 25 + 81 + 0}{6}}$ $\sigma = \sqrt{\frac{200}{6}} = \sqrt{\frac{100}{3}} = \frac{10}{\sqrt{3}}$.

$X$	$c$	$2c$	$3c$	$4c$	$5c$	$6c$
$f$	$2$	$1$	$1$	$1$	$1$	$1$

$A$ student scores the following marks in five tests: $54, 45, 41, 43, 57$. His score is not known for the sixth test. If the mean score is $48$ in six tests,then the standard deviation of marks in six tests is

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