frac{{{C_0}}}{1} + frac{{{C_1}}}{2} + frac{{{ | vedclass

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Question

(c) Proceeding as above and putting $n+1=N$.

So given term can be written as

$\frac{1}{N}\left\{ {{\,^N}{C_1} + {\,^N}{C_2} + {\,^N}{C_3} + ....

Vedclass · Accepted Answer

$\frac{{{2^{n + 1}} - 1}}{{n + 1}}$

Vedclass · Answer

(c) Proceeding as above and putting $n+1=N$.

So given term can be written as

$\frac{1}{N}\left\{ {{\,^N}{C_1} + {\,^N}{C_2} + {\,^N}{C_3} + ....} \right\}$

= $\frac{1}{N}\left\{ {{2^N} - 1} \right\} = \frac{1}{{n + 1}}({2^{n + 1}} - 1)$

$\frac{{{C_0}}}{1} + \frac{{{C_1}}}{2} + \frac{{{C_2}}}{3} + .... + \frac{{{C_n}}}{{n + 1}} = $

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