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(B) The horizontal range $R$ of a projectile launched horizontally from a height $H$ is given by the formula: $R = u \sqrt{\frac{2H}{g}}$.Given values

Vedclass · Accepted Answer

$40$

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(B) The horizontal range $R$ of a projectile launched horizontally from a height $H$ is given by the formula: $R = u \sqrt{\frac{2H}{g}}$.Given values are: initial horizontal velocity $u = 10 \ m/s$,height $H = 80 \ m$,and acceleration due to gravity $g = 10 \ m/s^2$.Substituting these values into the formula:$R = 10 	imes \sqrt{\frac{2 	imes 80}{10}}$$R = 10 	imes \sqrt{\frac{160}{10}}$$R = 10 	imes \sqrt{16}$$R = 10 	imes 4 = 40 \ m$.Therefore,the distance of the target from the foot of the building is $40 \ m$.

$A$ stone is projected horizontally with a speed $10 \ m/s$ from an $80 \ m$ high building. The distance of the target on the ground from the foot of the building is $.... \ m$ $(g = 10 \ m/s^2)$.

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