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(B) The bullets fired in all directions with speed $v$ will cover a circular area on the ground.The radius of this circle is equal to the maximum hori

Vedclass · Accepted Answer

$\pi \frac{v^4}{g^2}$

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(B) The bullets fired in all directions with speed $v$ will cover a circular area on the ground.The radius of this circle is equal to the maximum horizontal range $R_{\max}$ of the projectile.The formula for the horizontal range is $R = \frac{v^2 \sin(2	heta)}{g}$.The maximum range occurs at $	heta = 45^\circ$,where $R_{\max} = \frac{v^2}{g}$.The area $A$ covered by the bullets is the area of a circle with radius $R_{\max}$,given by $A = \pi R_{\max}^2$.Substituting the value of $R_{\max}$,we get $A = \pi \left( \frac{v^2}{g} ight)^2 = \frac{\pi v^4}{g^2}$.

$A$ large number of bullets are fired in all directions with the same speed $v$. What is the maximum area on the ground on which these bullets will spread?

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