$|{z_1} + {z_2}| = |{z_1}| + |{z_2}|$ is possible if

The points in the set $\{z \in \mathbb{C} : \arg \left(\frac{z-2}{z-6i}\right) = \frac{\pi}{2}\}$ (where $\mathbb{C}$ denotes the set of all complex numbers) lie on the curve which is a

If $z = x + iy$ is a complex number and $|1 + iz| = |1 - iz|$, then

$\sinh(ix)$ is equal to

If $\omega_1$ and $\omega_2$ are two non-zero complex numbers and $a, b$ are non-zero real numbers such that $|a \omega_1 + b \omega_2| = |a \omega_1 - b \omega_2|$,then $\frac{\omega_1}{\omega_2}$ is

Let $S$ be the set of all complex numbers $z$ satisfying $|z-2+i| \geq \sqrt{5}$. If the complex number $z_0$ is such that $\frac{1}{|z_0-1|}$ is the maximum of the set $\left\{\frac{1}{|z-1|}: z \in S\right\}$,then the principal argument of $\frac{4-z_0-\bar{z}_0}{z_0-\bar{z}_0+2i}$ is