$\sum\limits_{n = 1}^n {{1 \over {{{\log }_{{2^n}}}(a)}}} = $
${{n(n + 1)} \over 2}{\log _a}2$
${{n(n + 1)} \over 2}{\log _2}a$
${{{{(n + 1)}^2}{n^2}} \over 4}{\log _2}a$
એકપણ નહી.
જો ${a^2} + 4{b^2} = 12ab $ તો $\log (a + 2b)= . . .$ .
જો ${\log _{0.3}}(x - 1) < {\log _{0.09}}(x - 1),$ તો $x$ નો અંતરાલ મેળવો.
$32\root 5 \of 4 $ to the base $2\sqrt 2 = . . . .$
સરવાળો $\sum \limits_{n=1}^{\infty} \frac{2 n^2+3 n+4}{(2 n) !}= ..............$
${81^{(1/{{\log }_5}3)}} + {27^{{{\log }_{_9}}36}} + {3^{4/{{\log }_{_7}}9}} = . . . .$