$\sum \limits_{ k =0}^6{ }^{51- k } C _3$ is equal to
$\sum \limits_{ k =0}^6{ }^{51- k } C _3$ is equal to
- [JEE MAIN 2023]
- A
${ }^{51} C _4-{ }^{45} C _4$
- B
${ }^{51} C _3-{ }^{45} C _3$
- C
${ }^{52} C _4-{ }^{45} C _4$
- D
${ }^{52} C _3-{ }^{45} C _3$
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