tan theta + cot theta = ldots ldots ldots | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) We know that $	an 	heta = \frac{\sin 	heta}{\cos 	heta}$ and $\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$.Substituting these into the expre

Vedclass · Accepted Answer

$\operatorname{cosec} 	heta \cdot \sec 	heta$

Vedclass · Answer

(D) We know that $	an 	heta = \frac{\sin 	heta}{\cos 	heta}$ and $\cot 	heta = \frac{\cos 	heta}{\sin 	heta}$.Substituting these into the expression: $	an 	heta + \cot 	heta = \frac{\sin 	heta}{\cos 	heta} + \frac{\cos 	heta}{\sin 	heta}$.Taking the common denominator: $\frac{\sin^2 	heta + \cos^2 	heta}{\sin 	heta \cos 	heta}$.Using the trigonometric identity $\sin^2 	heta + \cos^2 	heta = 1$,we get: $\frac{1}{\sin 	heta \cos 	heta}$.Since $\frac{1}{\sin 	heta} = \operatorname{cosec} 	heta$ and $\frac{1}{\cos 	heta} = \sec 	heta$,the expression simplifies to $\operatorname{cosec} 	heta \cdot \sec 	heta$.

$\tan \theta + \cot \theta = \ldots \ldots \ldots$

Similar Questions

$\frac{1}{\cos ^{2} \theta}-1 = \ldots$

If $a \sin \theta = 3$ and $a \cos \theta = 4$,then $a = \dots$ (where $a > 0$).

Show that $\tan ^{4} \theta+\tan ^{2} \theta=\sec ^{4} \theta-\sec ^{2} \theta$

$(\sin 80^{\circ} + \cos 10^{\circ})(\sin 80^{\circ} - \cos 10^{\circ}) = \ldots \ldots \ldots$

Write 'True' or 'False' and justify your answer.
$(\tan \theta+2)(2 \tan \theta+1)=5 \tan \theta+\sec ^{2} \theta$

Vedclass Test Series

Exam Paper Generator

Online Exam Module