$\frac{1}{\cos ^{2} \theta}-1 = \ldots$
- A$\sin ^{2} \theta$
- B$\cot ^{2} \theta$
- C$\tan ^{2} \theta$
- D$\operatorname{cosec}^{2} \theta$
Explore More
Similar Questions
Prove that,$(\sin \alpha+\cos \alpha)(\tan \alpha+\cot \alpha)=\sec \alpha+\operatorname{cosec} \alpha$
Medium
View SolutionWhich of the following pairs is correct for trigonometric inter-relationships?
$1. \cos \theta$ $a. \frac{\cos \theta}{\sin \theta}$ $2. \tan \theta$ $b. \frac{1}{\csc \theta}$ $3. \cot \theta$ $c. \frac{1}{\sec \theta}$ $4. \sin \theta$ $d. \frac{1}{\cot \theta}$ $e. \sin \theta \cdot \cos \theta$
| $1. \cos \theta$ | $a. \frac{\cos \theta}{\sin \theta}$ |
| $2. \tan \theta$ | $b. \frac{1}{\csc \theta}$ |
| $3. \cot \theta$ | $c. \frac{1}{\sec \theta}$ |
| $4. \sin \theta$ | $d. \frac{1}{\cot \theta}$ |
| $e. \sin \theta \cdot \cos \theta$ |
Easy
View SolutionIf $\sin \theta + \cos \theta = p$ and $\sec \theta + \operatorname{cosec} \theta = q,$ then prove that $q(p^2 - 1) = 2p$.
Difficult
View Solution$\frac{\sec \theta-1}{\sec \theta+1} = \ldots$
Easy
View SolutionIf $\tan \theta = \frac{4}{3}$,then $\frac{5 \sin \theta + 2 \cos \theta}{3 \sin \theta - \cos \theta} = \ldots \ldots$
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo