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(D) Given that $AB$ is a chord of a circle with centre $P$. Point $C$ is a point on the major arc $AB$.We are given that $\angle APB = 130^{\circ}$.Ac

Vedclass · Accepted Answer

$65$

Vedclass · Answer

(D) Given that $AB$ is a chord of a circle with centre $P$. Point $C$ is a point on the major arc $AB$.We are given that $\angle APB = 130^{\circ}$.According to the circle theorem,the angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.Therefore,$\angle APB = 2 \angle ACB$.Substituting the given value:$130^{\circ} = 2 \angle ACB$$\angle ACB = \frac{130^{\circ}}{2} = 65^{\circ}$.Thus,$\angle ACB = 65^{\circ}$.

$AB$ is a chord of a circle with centre $P$. Point $C$ is a point other than $A$ and $B$ on the major arc $AB$. If $\angle APB = 130^{\circ}$,then find $\angle ACB$. (in $^{\circ}$)

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