(sin 80^{circ} + cos 10^{circ})(sin 80^{circ} | vedclass

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Question

(C) આપણે જાણીએ છીએ કે $\sin(90^{\circ} - 	heta) = \cos 	heta$.તેથી,$\sin 80^{\circ} = \sin(90^{\circ} - 10^{\circ}) = \cos 10^{\circ}$.આ કિંમતને આપે

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(C) આપણે જાણીએ છીએ કે $\sin(90^{\circ} - 	heta) = \cos 	heta$.તેથી,$\sin 80^{\circ} = \sin(90^{\circ} - 10^{\circ}) = \cos 10^{\circ}$.આ કિંમતને આપેલ પદાવલિમાં મૂકતા:$(\cos 10^{\circ} + \cos 10^{\circ})(\cos 10^{\circ} - \cos 10^{\circ})$$= (2 \cos 10^{\circ})(0)$$= 0$.

$(\sin 80^{\circ} + \cos 10^{\circ})(\sin 80^{\circ} - \cos 10^{\circ}) = \ldots \ldots \ldots$

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