ABCD is a quadrilateral whose diagonal AC div | vedclass

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Question

(A) diagonal of a quadrilateral divides it into two triangles. If the area of these two triangles is equal,it implies that the diagonal bisects the ar

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need not be any of $(B), (C)$ or $(D)$

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(A) diagonal of a quadrilateral divides it into two triangles. If the area of these two triangles is equal,it implies that the diagonal bisects the area of the quadrilateral.While it is true that the diagonal of a parallelogram divides it into two triangles of equal area,the converse is not necessarily true for all quadrilaterals.For example,a kite or any general quadrilateral where the diagonal divides the area into two equal parts does not have to be a parallelogram,a rhombus,or a rectangle.Therefore,$ABCD$ need not be any of the specific types mentioned in options $(B), (C),$ or $(D)$.

$ABCD$ is a quadrilateral whose diagonal $AC$ divides it into two parts of equal area. Then $ABCD$:

Similar Questions

In the figure,$BD \parallel CA$,$E$ is the mid-point of $CA$,and $BD = \frac{1}{2} CA$. Prove that $\operatorname{ar}(ABC) = 2 \operatorname{ar}(DBC)$.

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