$\frac{1}{\sqrt{9}-\sqrt{8}}$ is equal to
$\frac{1}{\sqrt{9}-\sqrt{8}}$ is equal to
- A
$\frac{1}{2}(3-2 \sqrt{2})$
- B
$3+2 \sqrt{2}$
- C
$3-2 \sqrt{2}$
- D
$\frac{1}{3+2 \sqrt{2}}$
Similar Questions
State whether each of the following statements is true or false
$\sqrt{3} \times \sqrt{5}=\sqrt{8}$
State whether each of the following statements is true or false
$\sqrt{3} \times \sqrt{5}=\sqrt{8}$
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Show that $0.142857142857 \ldots=\frac{1}{7}$
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Find the values of each of the following correct to three places of decimals, rationalising the denominator if needed and taking $\sqrt{2}=1.414$ $\sqrt{3}=1.732$ and $\sqrt{5}=2.236$
$\frac{\sqrt{10}-\sqrt{5}}{2}$
Find the values of each of the following correct to three places of decimals, rationalising the denominator if needed and taking $\sqrt{2}=1.414$ $\sqrt{3}=1.732$ and $\sqrt{5}=2.236$
$\frac{\sqrt{10}-\sqrt{5}}{2}$