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(B) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting a sum less than $6$.The

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$\frac{5}{18}$

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(B) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting a sum less than $6$.The possible outcomes for the sum being less than $6$ are:Sum $= 2: (1, 1)$Sum $= 3: (1, 2), (2, 1)$Sum $= 4: (1, 3), (2, 2), (3, 1)$Sum $= 5: (1, 4), (2, 3), (3, 2), (4, 1)$Counting these,we get $n(A) = 1 + 2 + 3 + 4 = 10$.The probability $P(A) = \frac{n(A)}{n(S)} = \frac{10}{36} = \frac{5}{18}$.

$2$ dice are thrown. Find the probability of getting a sum less than $6$.

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