sqrt{176+sqrt{2401}} = ? | vedclass

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Question

(B) First,find the square root of $2401$. Since $40^2 = 1600$ and $50^2 = 2500$,the number ends in $1$,so it must be $41$ or $49$. Checking $49^2$: $4

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) First,find the square root of $2401$. Since $40^2 = 1600$ and $50^2 = 2500$,the number ends in $1$,so it must be $41$ or $49$. Checking $49^2$: $49 	imes 49 = 2401$.Therefore,$\sqrt{2401} = 49$.Now,substitute this value into the expression: $\sqrt{176 + 49}$.Calculate the sum: $176 + 49 = 225$.Finally,find the square root of $225$: $\sqrt{225} = 15$.

$\sqrt{176+\sqrt{2401}} = ?$

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