$24$ is divided into two parts such that $7$ times the first part added to $5$ times the second part makes $146$. The first part is

How many numbers up to $200$ are divisible by both $2$ and $3$?

Which one of the following is the greatest number of five digits divisible by $231$?

$7372 \times 7372 + 7372 \times 628 = ?$

$\left[(72)^{2} \div 36+(?)^{2}\right] \div 5=45$

$A$ number consists of two digits such that the digit in the ten's place is less by $2$ than the digit in the unit's place. Three times the number added to $\frac{6}{7}$ times the number obtained by reversing the digits equals $108$. The sum of the digits in the number is: