left[(72)^{2} div 36+(?)^{2}right] div 5=45 | vedclass

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Question

(A) Let the missing number be $x$.Given equation: $[(72)^{2} \div 36 + x^{2}] \div 5 = 45$Step $1$: Multiply both sides by $5$:$(72)^{2} \div 36 + x^{

Vedclass · Accepted Answer

$9$

Vedclass · Answer

(A) Let the missing number be $x$.Given equation: $[(72)^{2} \div 36 + x^{2}] \div 5 = 45$Step $1$: Multiply both sides by $5$:$(72)^{2} \div 36 + x^{2} = 45 	imes 5$$(72)^{2} \div 36 + x^{2} = 225$Step $2$: Simplify $(72)^{2} \div 36$:$(5184) \div 36 + x^{2} = 225$$144 + x^{2} = 225$Step $3$: Solve for $x^{2}$:$x^{2} = 225 - 144$$x^{2} = 81$Step $4$: Find $x$:$x = \sqrt{81} = 9$Therefore,the missing number is $9$.

$\left[(72)^{2} \div 36+(?)^{2}\right] \div 5=45$

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