frac{753 times 753 + 247 times 247 - 753 time | vedclass

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Question

(A) Let $a = 753$ and $b = 247$.The given expression is of the form $\frac{a^2 + b^2 - ab}{a^3 + b^3}$.Using the algebraic identity $a^3 + b^3 = (a +

Vedclass · Accepted Answer

$\frac{1}{1000}$

Vedclass · Answer

(A) Let $a = 753$ and $b = 247$.The given expression is of the form $\frac{a^2 + b^2 - ab}{a^3 + b^3}$.Using the algebraic identity $a^3 + b^3 = (a + b)(a^2 + b^2 - ab)$,we can rewrite the expression as:$\frac{a^2 + b^2 - ab}{(a + b)(a^2 + b^2 - ab)} = \frac{1}{a + b}$.Substituting the values of $a$ and $b$:$\frac{1}{753 + 247} = \frac{1}{1000}$.

$\frac{753 \times 753 + 247 \times 247 - 753 \times 247}{753 \times 753 \times 753 + 247 \times 247 \times 247} = ?$

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