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(C) To find the remainder when $3401$ is divided by $11$,we perform the division:$3401 \div 11 = 309$ with a remainder.$3401 = 11 	imes 309 + 2$.Alte

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$2$

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(C) To find the remainder when $3401$ is divided by $11$,we perform the division:$3401 \div 11 = 309$ with a remainder.$3401 = 11 	imes 309 + 2$.Alternatively,using the divisibility rule for $11$: The difference between the sum of digits at odd places and even places is $(3+0) - (4+1) = 3 - 5 = -2$.Since the result is $-2$,we add $11$ to get the positive remainder: $-2 + 11 = 9$.Wait,let's re-calculate: $3401 \div 11$: $3401 = 11 	imes 309 + 2$.The remainder is $2$.Therefore,if we subtract $2$ from $3401$,the result $3399$ will be perfectly divisible by $11$ $(3399 \div 11 = 309)$.

What least number should be subtracted from $3401$ so that the result is completely divisible by $11$?

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