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(C) Let the length of the other train be $x \, m$.Since the trains are moving in opposite directions,their relative speed is the sum of their individu

Vedclass · Accepted Answer

$260$

Vedclass · Answer

(C) Let the length of the other train be $x \, m$.Since the trains are moving in opposite directions,their relative speed is the sum of their individual speeds:Relative speed $= (62 + 40) \, km/h = 102 \, km/h$.Convert the relative speed into $m/s$ by multiplying by $\frac{5}{18}$:Relative speed $= 102 	imes \frac{5}{18} = \frac{510}{18} = \frac{85}{3} \, m/s$.The total distance covered when crossing each other is the sum of the lengths of the two trains,which is $(250 + x) \, m$.Using the formula $	ext{Distance} = 	ext{Speed} 	imes 	ext{Time}$:$250 + x = \left(\frac{85}{3}ight) 	imes 18$$250 + x = 85 	imes 6$$250 + x = 510$$x = 510 - 250 = 260 \, m$.Thus,the length of the other train is $260 \, m$.

Two trains are running in opposite directions with speeds of $62 \, km/h$ and $40 \, km/h$,respectively. If the length of one train is $250 \, m$ and they cross each other in $18 \, seconds$,then the length of the other train is (in $m$):

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