Match the reactions given in Column-$I$ with the bond broken in Column-$II$.

Column-$I$ (Reaction)	Column-$II$ (Bond broken)
$(A)$ $RCH_2OH \xrightarrow{CrO_3} RCHO$	$(i)$ $C-O$ bond breaks.
$(B)$ Phenol $\xrightarrow{HNO_3}$ $p$-Nitrophenol + $o$-Nitrophenol	(ii) $O-H$ bond breaks.
$(C)$ Phenol + $NaOH \rightarrow$ Sodium phenoxide + $H_2O$	(iii) $O-H$ and $C-H$ bonds break.
$(D)$ $CH_3CH_2CH_2OH \xrightarrow{H_2SO_4, \Delta} CH_3CH=CH_2$	(iv) $C-H$ bond breaks.

(A-III, B-IV, C-II, D-I) $(A) \rightarrow (iii)$: In the oxidation of primary alcohol to aldehyde using $CrO_3$,both $O-H$ and $C-H$ bonds are broken.
$(B) \rightarrow (iv)$: In the nitration of phenol,the electrophilic substitution occurs on the ring,involving the breaking of a $C-H$ bond on the benzene ring.
$(C) \rightarrow (ii)$: The reaction of phenol with $NaOH$ is an acid-base reaction where the $O-H$ bond of the phenol breaks to form phenoxide ion.
$(D) \rightarrow (i)$: The dehydration of alcohol to alkene involves the breaking of the $C-O$ bond (along with a $C-H$ bond,but $C-O$ is the primary bond cleavage characteristic of this elimination).
Correct matching: $(A-iii, B-iv, C-ii, D-i)$.