The major product in the following reaction s | vedclass

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Question

(A) The reaction proceeds as follows:$(i)$ Phenol reacts with $NaOH$ and $CH_3I$ to form anisole (methoxybenzene) via Williamson ether synthesis.(ii)

Vedclass · Accepted Answer

$1-$($4$-methoxyphenyl)propan$-1-$ol

Vedclass · Answer

(A) The reaction proceeds as follows:$(i)$ Phenol reacts with $NaOH$ and $CH_3I$ to form anisole (methoxybenzene) via Williamson ether synthesis.(ii) Anisole undergoes Friedel-Crafts acylation with propionyl chloride $(CH_3CH_2COCl)$ in the presence of anhydrous $AlCl_3$. Since the $-OCH_3$ group is ortho/para-directing,and the para-position is sterically less hindered,the major product is $p$-methoxypropiophenone.(iii) Reduction of the ketone group with $NaBH_4$ yields the corresponding secondary alcohol,$1$-($4$-methoxyphenyl)propan$-1-$ol.Therefore,the correct option is $A$.

List-$I$	List-$II$
$A$. $H_{3}C-CH(OH)-CH_{3}$	$I$. $(i)$ oleum; (ii) $NaOH, \Delta$; (iii) $H^{+}$
$B$. $CH_{3}COOH \rightarrow CH_{3}CH_{2}OH$	$II$. $(i)$ $O_{2}$; (ii) $H_{2}O/H^{+}$
$C$. $CH_{3}CH_{2}OH \rightarrow H_{3}C-CH(OH)-CH_{3}$	$III$. $(i)$ $CH_{3}OH, H^{+}$; (ii) $H_{2}$,Catalyst
$D$. Benzene $\rightarrow$ Phenol	$IV$. $(i)$ conc. $H_{2}SO_{4}, \Delta$; (ii) $H^{+}/H_{2}O$

The major product in the following reaction sequence is:

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In the following reaction,$\text{Phenol}$ $\xrightarrow{Zn \, \text{dust}} x$ $\xrightarrow[\text{Anhy.} \, ZnCl_2]{CH_3Cl} y$ $\xrightarrow{\text{Alk.} \, KMnO_4} z$. The product $z$ is:

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:

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