Arrange the following in the increasing order of their bond dissociation energy: $O_2$,$O_2^+$,$O_2^-$,and $O_2^{2-}$.

Although $CN^{-}$ ion and $N_2$ molecule are isoelectronic,yet $N_2$ molecule is chemically inert because of

Consider the following statements.
$I$. In the conversion of $O_2$ to $O_2^{2+}$,bond order decreases.
$II$. In the conversion of $O_2$ to $O_2^{2+}$,magnetic property is not changed.
$III$. In the conversion of $O_2$ to $O_2^{2+}$,bond length decreases.
$IV$. $O_2^{2-}$ and $B_2$ have same bond order.
Identify the correct statements.

Consider the ions/molecule $O_{2}^{+}, O_{2}, O_{2}^{-}, O_{2}^{2-}$. For increasing bond order,the correct option is ..... .

If $N_x$ is the number of bonding orbitals of an atom and $N_y$ is the number of antibonding orbitals,then the molecule/atom will be stable if

If the bond order in $C_2$ is '$x$',then the bond order in $B_2$ and $O_2$,respectively,are