At which location on Earth is the value of $g$ maximum? State the reasons.
(N/A) The value of $g$ is maximum at the poles.
Reasons:
$(i)$ The radius of the Earth is slightly smaller at the poles compared to the equator. Since $g = \frac{GM}{R^2}$,a smaller $R$ leads to a larger $g$.
$(ii)$ At the poles,the centrifugal force due to the Earth's rotation is zero,which means there is no reduction in the effective gravitational acceleration.
Reasons:
$(i)$ The radius of the Earth is slightly smaller at the poles compared to the equator. Since $g = \frac{GM}{R^2}$,a smaller $R$ leads to a larger $g$.
$(ii)$ At the poles,the centrifugal force due to the Earth's rotation is zero,which means there is no reduction in the effective gravitational acceleration.
Explore More
Similar Questions
State the values of $g$ and $G$ at the center of the Earth. Identify which of $g$ and $G$ is a vector and which is a scalar.
Medium
View SolutionThe rotation of the Earth (of radius $R$) about its axis speeds up to a value such that a man at latitude angle $45^{\circ}$ feels weightlessness. The duration of a day in such a case is
DifficultAP EAMCET 2021
View Solution$A$ body weighs $72 \ N$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth (in $N$)?
MediumAIPMT 2000
View SolutionIf two planets have their radii in the ratio $x: y$ and densities in the ratio $m: n$,then the ratio of the acceleration due to gravity on them is
$A$ box weighs $196 \; N$ on a spring balance at the North Pole. Its weight recorded on the same balance if it is shifted to the equator is close to ....... $N$ (Take $g = 10 \; m/s^2$ at the North Pole and the radius of the Earth $R = 6400 \; km$).
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo