An element has a bcc structure. If its edge l | vedclass

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(A) Given: $bcc$ structure,$Z = 2$,$a = 250 \, pm = 250 	imes 10^{-10} \, cm$,$d = 8 \, g/cm^3$,$N_A = 6.022 	imes 10^{23} \, mol^{-1}$.Using the fo

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$M = 37.64 \, g/mol, r = 108.25 \, pm$

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(A) Given: $bcc$ structure,$Z = 2$,$a = 250 \, pm = 250 	imes 10^{-10} \, cm$,$d = 8 \, g/cm^3$,$N_A = 6.022 	imes 10^{23} \, mol^{-1}$.Using the formula $d = \frac{Z 	imes M}{a^3 	imes N_A}$:$M = \frac{d 	imes a^3 	imes N_A}{Z} = \frac{8 	imes (250 	imes 10^{-10})^3 	imes 6.022 	imes 10^{23}}{2}$.$M = 4 	imes 15.625 	imes 10^{-24} 	imes 6.022 	imes 10^{23} = 37.6375 \approx 37.64 \, g/mol$.For $bcc$ structure,the relation between radius $r$ and edge length $a$ is $r = \frac{\sqrt{3}}{4} 	imes a$.$r = \frac{1.732}{4} 	imes 250 \, pm = 0.433 	imes 250 = 108.25 \, pm$.

An element has a $bcc$ structure. If its edge length is $250 \, pm$ and its density is $8 \, g/cm^3$,calculate its molar mass and the radius of the atom.

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