In a body-centred cubic $(bcc)$ lattice of potassium,the correct relation between the atomic radius $(r)$ of potassium and the edge-length $(a)$ of the cube is:
- A$r = \frac{a}{\sqrt{2}}$
- B$r = \frac{a}{\sqrt{3}}$
- C$r = \frac{\sqrt{3}}{2} a$
- D$r = \frac{\sqrt{3}}{4} a$
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Similar Questions
How many unit cells are present in a cube-shaped ideal crystal of $NaCl$ of mass $1 \ g$?
Calculate the edge length of a unit cell that crystallizes to form a $BCC$ structure. (Radius of atom is $2.17 \times 10^{-8} \ cm$,$\sqrt{3} = 1.732$)
Calculate the molar mass of an element if it forms $fcc$ unit cell structure. [Mass of unit cell $= 1.8 \times 10^{-22} \ g$,$N_A = 6.022 \times 10^{23} \ mol^{-1}$]
DifficultMHT CET 2025
View SolutionCalculate the number of unit cells in $58.5 \, g$ of $NaCl$ crystallizing in an $fcc$ structure. $(NaCl = 58.5 \, g/mol)$
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View SolutionDerive the expression for the density $(d)$ of a unit cell: $d = \frac{zM}{a^3 N_A}$.
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