The formula for the determination of the density of a unit cell is:

  • A
    $\frac{a^3 \times N_A}{Z \times M} \ g \ cm^{-3}$
  • B
    $\frac{Z \times M}{a^3 \times N_A} \ g \ cm^{-3}$
  • C
    $\frac{a^3 \times M}{Z \times N_A} \ g \ cm^{-3}$
  • D
    $\frac{M \times N_A}{a^3 \times Z} \ g \ cm^{-3}$

Explore More

Similar Questions

If the edge length of a cubic unit cell in a $bcc$ structure is $400 \, pm$, then the atomic radius of the metal will be ........... $pm$.

Difficult
View Solution

Calculate the number of unit cells in $10 \, g$ of $CsCl$ which crystallizes in a $bcc$ structure. $(CsCl = 168.5 \, amu)$

Iron exhibits $bcc$ structure at room temperature. Above $500^{\circ} C$,it transforms to $fcc$ structure. Find the ratio of the density of iron at room temperature to that at $500^{\circ} C$. (Assume the atomic radii and the molar mass of iron remain constant even with variation in temperature)

Calculate the edge length of $fcc$ unit cell if the radius of the metal atom is $139 \ pm$.

An element with atomic mass $100$ has a $bcc$ structure and edge length $400 \, pm$. The density of the element is .............. $g \, cm^{-3}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo