How can the impulse of a force be determined when a large force acts on an object for a very short interval of time?

  • A
    By calculating the change in momentum.
  • B
    By calculating the work done.
  • C
    By calculating the change in kinetic energy.
  • D
    By calculating the average velocity.

Explore More

Similar Questions

$A$ particle of mass $2 \ kg$ is initially at rest. $A$ force acts on it whose magnitude changes with time. The force-time graph is shown below. The velocity of the particle after $10 \ s$ is $.... \ ms^{-1}$.

$A$ force-time graph for a linear motion is shown in the figure,where the segments are circular. The linear momentum gained between $0$ and $8$ seconds is

$A$ force of $50\, dynes$ acts on a body of mass $5\, g$ which is at rest for an interval of $3\, seconds$. The impulse is:

$A$ mass of $100\,g$ strikes the wall with a speed of $5\,m/s$ at an angle as shown in the figure and it rebounds with the same speed. If the contact time is $2 \times 10^{-3}\,s$,what is the force applied on the mass by the wall?

The magnitude of force acting on a particle moving along the $x$-axis varies with time $(t)$ as shown in the figure. If at $t=0$ the velocity of the particle is $v_0$,then its velocity at $t=T_0$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo