$(CH_3)_3CCHO$ does not undergo aldol condensation due to

Compare the rate of reaction toward Beckmann rearrangement for the given oxime derivatives where $\gamma$ is: $(i) CH_3COO^-$,$(ii) ClCH_2COO^-$,$(iii) PhSO_3^-$.

Predict the product when the given compound $(A)$ reacts with $NaBH_4$.

The product $(C)$ of the reaction is:

An organic compound $x$ where the molar ratio of $C$,$O$,and $H$ are equal,on treatment with $50\% \ KOH$ under reflux followed by acidification produced $y$. The most likely structure of $y$ is: [Molar mass of $x$ is $58 \ g \ mol^{-1}$]

The compound $A$ in the following reaction is:
$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$
$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$