The product (C) of the reaction is: | vedclass

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(A) The given reaction is a haloform reaction followed by decarboxylation. $1$. The starting material is $1$-acetyl-$1$-methylcyclohexane. $2$. Treatm

Vedclass · Accepted Answer

$2-$methylcyclohexanone

Vedclass · Answer

(A) The given reaction is a haloform reaction followed by decarboxylation. $1$. The starting material is $1$-acetyl-$1$-methylcyclohexane. $2$. Treatment with $Br_2   NaOH$ (haloform reaction) converts the $-COCH_3$ group into a carboxylate salt $(-COO^-)$,forming the intermediate $(A)$ which is the salt of a $\beta$-keto acid. $3$. Upon acidification $(H^ )$ and heating $(\Delta)$,the $\beta$-keto acid undergoes decarboxylation (loss of $CO_2$) to yield $2$-methylcyclohexanone as the final product $(C)$.

The product $(C)$ of the reaction is:

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