Difficult
Identify $Z$ in the following sequence:
${C_3}{H_7}OH$ $\xrightarrow{conc. \ H_2SO_4} X$ $\xrightarrow{Br_2} Y$ $\xrightarrow[alc. \ KOH]{high \ level} Z$
${C_3}{H_7}OH$ $\xrightarrow{conc. \ H_2SO_4} X$ $\xrightarrow{Br_2} Y$ $\xrightarrow[alc. \ KOH]{high \ level} Z$
- A$CH_3-CH(NH_2)-CH_2(NH_2)$
- B$CH_3-CH(OH)-CH_2(OH)$
- C$CH_3-C(OH)=CH_2$
- D$CH_3-C \equiv CH$
Explore More
Similar Questions
How can propyne and propene be distinguished?
Medium
View SolutionBy heating a mixture of $CHCl_3$ with silver powder,the compound formed is
Difficult
View Solution$HC \equiv CH$ $\xrightarrow[{excess}]{{CH_3MgBr}} \mathop {(A)}\limits_{\text{salt}} + \mathop {(B)}\limits_{\text{hydrocarbon}}$
$(A)$ $\xrightarrow[{excess}]{{CH_3I}} (C)$ $\xrightarrow[{(ii) H^{+} }]{{(i) NaNH_2}} (D)$
$(A)$ $\xrightarrow[{excess}]{{CH_3I}} (C)$ $\xrightarrow[{(ii) H^{+} }]{{(i) NaNH_2}} (D)$
Two moles of $HBr$ are added to $CH_3-C \equiv CH$ in the presence of peroxide to give:
Medium
View SolutionIdentify the structure of $M$ based on the following reaction scheme:
MediumWBJEE 2023
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo