The reaction of a mixture of two alkyl halides with sodium in ether gives $2-$methylpropane. The alkyl halides are:

  • A
    $2-$chloropropane and chloromethane
  • B
    $2-$chloropropane and chloroethane
  • C
    chloromethane and chloroethane
  • D
    chloromethane and $1-$chloropropane

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Similar Questions

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

The product obtained on reaction of $C_2H_5Cl$ with hydrogen over palladium carbon is

Isopropyl chloride undergoes hydrolysis by which mechanism?

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In the reaction of $2$-chlorobutane with aqueous $KOH$,the product $A$ formed is:

The major product of the following reaction is:

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