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(B) The reaction is an $E2$ elimination reaction of a secondary alkyl chloride with a strong base $(NaOEt)$.According to Saytzeff's rule,the major pro

Vedclass · Accepted Answer

$CH_3-C(CO_2CH_2CH_3)=CH-CH_3$

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(B) The reaction is an $E2$ elimination reaction of a secondary alkyl chloride with a strong base $(NaOEt)$.According to Saytzeff's rule,the major product is the more substituted alkene,as it is more stable.In the given substrate,$CH_3-CH(Cl)-CH_2-CH_3$ (with a $CO_2Et$ group),the elimination of $HCl$ can occur from either the $CH_3$ group or the $CH_2$ group.Elimination from the $CH_2$ group leads to a trisubstituted alkene $(CH_3-C(CO_2Et)=CH-CH_3)$,which is more stable than the disubstituted alkene $(CH_3-CH_2-C(CO_2Et)=CH_2)$ formed by elimination from the $CH_3$ group.Therefore,the major product is $CH_3-C(CO_2CH_2CH_3)=CH-CH_3$.

The major product of the following reaction is:

Similar Questions

Which one of the following is not true for the hydrolysis of $t$-butyl bromide with aqueous $NaOH$?

What is the principal product of the following reaction?
$CH_3-CH(Br)-CH_2-CH_2-CH(Cl)-CH_3 + NaN_3 \rightarrow \text{Product}$

The major product in the reaction is:

Arrange the following compounds in order of increasing $S_N1$ reaction rate:
$(i)$ $Ph-C(CH_3)_2-Br$
(ii) $CH_3-CH_2-CH(CH_3)-Br$
(iii) $(CH_3)_3C-Br$
(iv) $CH_3-CH_2-CH(CH_3)-Cl$

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