In the reaction of 2-chlorobutane with aqueou | vedclass

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(B) The reaction of $2$-chlorobutane with aqueous $KOH$ proceeds via an $S_N1$ mechanism because $2$-chlorobutane is a secondary alkyl halide. In the

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Racemic mixture

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(B) The reaction of $2$-chlorobutane with aqueous $KOH$ proceeds via an $S_N1$ mechanism because $2$-chlorobutane is a secondary alkyl halide. In the $S_N1$ mechanism,the rate-determining step involves the formation of a planar carbocation intermediate. The nucleophile $(OH^-)$ can attack the planar carbocation from either side with equal probability. This leads to the formation of both $(R)$ and $(S)$ enantiomers in equal amounts,resulting in a racemic mixture.

In the reaction of $2$-chlorobutane with aqueous $KOH$,the product $A$ formed is:

Similar Questions

The decreasing order of the rate of $S_{N^1}$ reaction for the following compounds is:
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The order of the rate of $S_N1$ reactivity for the following compounds is:

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