The hexafluoroferrate (II) ion is an outer or | vedclass

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(C) The formula for the hexafluoroferrate $(II)$ ion is $[FeF_6]^{4-}$.In this complex,the oxidation state of $Fe$ is $+2$.The electronic configuratio

Vedclass · Accepted Answer

$4$

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(C) The formula for the hexafluoroferrate $(II)$ ion is $[FeF_6]^{4-}$.In this complex,the oxidation state of $Fe$ is $+2$.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.Since $F^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Thus,the $3d$ orbitals contain $5$ electrons in the $t_{2g}$ and $e_g$ sets as follows: $t_{2g}^4 e_g^2$.The number of unpaired electrons is $4$.

The hexafluoroferrate $(II)$ ion is an outer orbital complex. The number of unpaired electrons in it is .............

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