The magnetic moment of the high spin complex | vedclass

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(C) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Given $\mu = 5.92 \ BM$,we h

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$t_{2g}^3 e_{g}^2$

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(C) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. Given $\mu = 5.92 \ BM$,we have $\sqrt{n(n+2)} = 5.92$. Solving for $n$,we get $n(n+2) \approx 35$,which implies $n = 5$. For a high spin octahedral complex with $5$ unpaired electrons,the electrons occupy the $t_{2g}$ and $e_g$ orbitals according to Hund's rule. The configuration is $t_{2g}^3 e_g^2$.

The magnetic moment of the high spin complex is $5.92 \ BM$. What is the electronic configuration?

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