EDTA^{4-} is the ethylenediaminetetraacetate | vedclass

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(B) $EDTA^{4-}$ is a hexadentate ligand that forms a complex with $Co^{3+}$ ion. In the $[Co(EDTA)]^{-}$ complex,the $Co^{3+}$ ion is octahedrally coo

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(B) $EDTA^{4-}$ is a hexadentate ligand that forms a complex with $Co^{3+}$ ion. In the $[Co(EDTA)]^{-}$ complex,the $Co^{3+}$ ion is octahedrally coordinated by two nitrogen atoms and four oxygen atoms from the $EDTA^{4-}$ ligand. To find the number of $N-Co-O$ bond angles,we look at the coordination geometry. Each nitrogen atom is bonded to the cobalt center and is part of three five-membered chelate rings. Specifically,each $N$ atom is involved in $N-Co-O$ angles with the oxygen atoms of the acetate groups. By analyzing the structure,each of the two $N$ atoms forms $4$ such $N-Co-O$ angles (where the $O$ atom is one of the four coordinated oxygen atoms). Therefore,the total number of $N-Co-O$ bond angles is $2 	imes 4 = 8$.

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

$EDTA^{4-}$ is the ethylenediaminetetraacetate ion. The total number of $N-Co-O$ bond angles in the $[Co(EDTA)]^{-}$ complex ion is:

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Match the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$ $(ii). [Ni(CO)_4]$
$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
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What is the number of unpaired electrons present in $[CoF_6]^{3-}$?

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