The reaction of CuSO_4 with excess KCN soluti | vedclass

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Question

(C) When $CuSO_4$ reacts with $KCN$,initially a precipitate of cupric cyanide $Cu(CN)_2$ is formed.$CuSO_4 + 2KCN \rightarrow Cu(CN)_2 + K_2SO_4$$Cu(C

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$K_3[Cu(CN)_4]$

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(C) When $CuSO_4$ reacts with $KCN$,initially a precipitate of cupric cyanide $Cu(CN)_2$ is formed.$CuSO_4 + 2KCN \rightarrow Cu(CN)_2 + K_2SO_4$$Cu(CN)_2$ is unstable and decomposes to give cuprous cyanide $CuCN$ and cyanogen gas $(CN)_2$.$2Cu(CN)_2 \rightarrow 2CuCN + (CN)_2$In the presence of excess $KCN$,$CuCN$ dissolves to form the stable complex potassium tetracyanocuprate$(I)$,$K_3[Cu(CN)_4]$.$CuCN + 3KCN \rightarrow K_3[Cu(CN)_4]$

The reaction of $CuSO_4$ with excess $KCN$ solution leads to the formation of:

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